Home › Learning › NCERT Solutions › Class 5 Maths › Maths Mela › Chapter 6 CLASS 5 · MATHS MELA · CHAPTER 6
The Dairy Farm Build flexible multiplication strategies, calculate large products and solve dairy, composting, money and array problems.
193 worked answers All 8 exercise sets
What you will learn Use place value and the distributive property to multiply. Choose doubling, halving, compensation or written multiplication. Check products with patterns and estimates. Find a topic or question Show all explanations
193 worked answers · short steps first, explanations when you need them
Let Us Think Textbook pages 70–71
Question 1
Find values from the six shape multiplication statements, using numbers 1–24. One consistent choice is rectangle=3 and circle=4, so triangle=12 and outlined shape=9.
Choose parallelogram=6 and diamond=2, so 6×2=12; diamond×pentagon=diamond gives pentagon=1; crescent=6×4=24.
Answer One valid assignment is rectangle 3, circle 4, triangle 12, outlined shape 9, parallelogram 6, diamond 2, pentagon 1 and crescent 24.
Question 2
Place 2, 5 and 3 as a two-digit number times a one-digit number to get closest to 100. Check the promising arrangements: 53×2=106 and 23×5=115.
106 is only 6 away from 100.
Answer 53×2=106, the closest possible.
Question 3
List rectangular arrangements containing 60 pouches. Factor pairs of 60 are 1×60, 2×30, 3×20, 4×15, 5×12 and 6×10.
Answer Possible arrangements: 1×60, 2×30, 3×20, 4×15, 5×12 and 6×10, in either order.
Question 4
Use the printed number clues to identify candidates. Multiples of 9 below 50 are 9,18,27,36,45; the odd ones not divisible by 4 or 11 are 9,27,45.
The additional statements “odd number” and “ones digit even” cannot both describe one whole number.
Answer The consistent first group gives 9, 27 or 45; if all eight lines are intended for one number, there is no solution because an odd number cannot have an even ones digit.
Question 5 · 0–20
Use two grid numbers and one operation to make 0–20. Which need more than two distinct entries? Examples: 1=5−4, 2=10÷5, 3=36÷12, 4=100÷25, 5=25÷5, 6=2×3, 7=5+2, 8=10−2, 9=12−3, 10=5×2.
11=36−25, 12=10+2, 13=25−12, 14=10+4, 15=25−10, 16=12+4, 17=12+5, 18=36÷2 and 20=100÷5.
Answer With two distinct grid entries, 1–18 except 19 and also 20 are possible; 0 and 19 need a repeated entry or three numbers.
Question 5 · three numbers
Show ways to make the missing 0 and 19 using three numbers. Answer 0=5−3−2 and 19=25−4−2.
Order and Place Value in Multiplication Textbook pages 72–74
Question Order 1
Find 3×2. Question Order 2
Find 2×3. Question Order 3
Find 8×5. Question Order 4
Find 5×8. Question Order 5
Find 10×5. Question Order 6
Find 5×10. Question Order 7
Find 8×20. Question Order 8
Find 20×8. Question Order 9
Find 12×9. Question Order 10
Find 9×12. Question Order 11
Find 6×13. Question Order 12
Find 13×6. Question Order 13
Find 9×0. Question Order 14
Find 0×9. Question 1(i)
Find 10×100. Question 2(a)
Find 100×90. Question 2(b)
Find 400×10. Question Table 1
Find 700×8. Question Table 2
Find 80×90. Question Table 3
Find 220×20. Question Table 4
Find 10×63. Question Table 5
Find 11×300. Question Table 6
Find 40×12. Question Thousands 1
Find 20×100. Question Thousands 2
Find 40×500. Question Thousands 3
Find 60×300. Question Thousands 4
Find 600×30. Question Thousands 5
Find 80×900. Question Thousands 6
Find 70×600. Question Thousands 7
Find 3×5,000. Question Thousands 8
Find 8×3,000. Question Thousands 9
Find 5×7,000. Question 18×5
Explain several correct ways to find 18×5. Split: 10×5+8×5=50+40=90.
Compensate: 20×5−2×5=100−10=90.
Double and halve: 9×10=90.
Doubling, Halving and Nearest Multiples Textbook pages 75–76
Question 3(c4)
Find 35×14. Question e
Give five products suited to doubling and halving. 6×15=3×30=90; 14×25=7×50=350; 16×35=8×70=560; 24×5=12×10=120; 18×50=9×100=900.
Answer Examples: 6×15=90, 14×25=350, 16×35=560, 24×5=120, 18×50=900.
Question Nearest 1
Use a nearby multiple to find 4×19. Question Nearest 2
Use a nearby multiple to find 14×21. Question Nearest examples
Give five products that are easy using a nearby round factor. 6×19=120−6=114; 8×31=240+8=248; 12×49=600−12=588; 25×39=1,000−25=975; 14×101=1,400+14=1,414.
Answer The five products are 114, 248, 588, 975 and 1,414.
Problems, Waste and Composting Textbook pages 77–78
Question 1
An auditorium has 35 rows of 42 seats. 35×42=35×40+35×2=1,400+70.
Question 2
Priya jogs 4 km daily for 31 days. Question 3
There are 36 boxes with 48 books each. 36×48=36×(50−2)=1,800−72.
Question 4
Four kurtas use 16 m of cloth. Find cloth for eight. Eight is twice four, so 16×2=32.
Question 5
Twenty-nine cows give 5 L each. Question 6
Each of 297 cows needs 18 kg fodder. 297×18=297×(20−2)=5,940−594.
Question Waste 1
A family produces 35 kg kitchen waste monthly. Find one year. Question Waste methods
Why do Nida, Kanti and John all get 35×12=420? Each method includes 30×10, 30×2, 5×10 and 5×2, either separately or grouped.
Answer They reorganise the same four partial products, so all total 420.
Question Waste 2
The family makes 150 kg compost worth ₹24 per kg. Find savings. 150×24=150×20+150×4=3,000+600.
Let Us Multiply Textbook pages 79–80
Question Example (a)
Find 32×8. Question Example (b)
Find 69×45. Question 4(a)
A theatre has 8 rows of 12 seats. Half fill, then 3 more rows fill. Total seats=8×12=96; half=48.
Three rows add 3×12=36; 48+36=84.
Question 4(b)
India hits twenty-four 4s and eighteen 6s, runs 234, and gets 23 extras. Find the total. Boundary fours=24×4=96; sixes=18×6=108.
96+108+234+23=461.
Answer 96 runs in fours, 108 in sixes, and 461 runs in total.
Question 4(c)
Find the cost of 15 bulbs at ₹25 and 12 tube lights at ₹34. 15×25=375; 12×34=408.
375+408=783.
Question 4(d)
Find earnings from 28 rice bags at ₹350 each. Question 4(e)
A library has 86 shelves with 162 books each. 162×86=162×80+162×6=12,960+972.
Dairy Cooperative and Large Products Textbook pages 81–84
Question 1
At least 4 cows each for 268 villagers. Find the minimum. Question 2
Each of 453 Gir cows gives 13 L. Find daily milk. 453×13=453×10+453×3=4,530+1,359.
Question 3
Sell 125 kg ghee at ₹574 per kg. 574×125=574×100+574×20+574×5.
57,400+11,480+2,870=71,750.
Question 1(c)
Find 324×18. Question 1(d)
Find 507×23. Question 1(e)
Find 190×65. Question 2(a)
Find 123×84. Question 2(b)
Find 368×32. Question 2(c)
Find 159×324. Question 2(d)
Find 239×401. Question 2(f)
Find 101×22. Question 3(b)
Find 143×28. Question 3(d)
Find 450×38. Question 3(e)
Find 584×23. Question 3(f)
Find 302×13. Question 3(g)
Find 604×54. Question 3(h)
Find 112×23. Question 3(i)
Find 237×19. Check and Find Equivalent Products Textbook pages 85–87
Question Check (a)
Check Asma’s 46×59 solution. 46×59=46×(60−1)=2,760−46=2,714.
Question Check (b)
Check Pankaj’s 203×54=135. 203×54=203×50+203×4=10,150+812.
Answer Incorrect; the product is 10,962.
Question Check (c)
Check Lado’s 38×150=5,700. 38×150=38×(100+50)=3,800+1,900.
Question Check (d)
Check Kira’s 193×272=40,337. 193×272=193×200+193×70+193×2.
38,600+13,510+386=52,496.
Answer Incorrect; the product is 52,496.
Question Check (e)
How should a column multiplication solution be checked? Recalculate by expansion, then estimate the size.
For example, hundreds times hundreds should produce a five-digit scale when appropriate.
Answer Every partial row must represent ones, tens or hundreds correctly; add them and compare with an estimate.
Question Same · 12×17
Which listed expressions equal 12×17? Use distribution or compensation without full multiplication.
Question Same · 26×11
Which listed expressions equal 26×11? Use distribution or compensation without full multiplication.
Answer 26×10+26×1 and 20×11+6×11.
Question Same · 18×4
Which listed expressions equal 18×4? Use distribution or compensation without full multiplication.
Question Same · 55×9
Which listed expressions equal 55×9? Use distribution or compensation without full multiplication.
Answer 50×9+5×9 and 55×10−55.
Question Same · 101×42
Which listed expressions equal 101×42? Use distribution or compensation without full multiplication.
Question Same · 247×8
Which listed expressions equal 247×8? Use distribution or compensation without full multiplication.
Question Same · 1,001×5
Which listed expressions equal 1,001×5? Use distribution or compensation without full multiplication.
Question Same · 1,999×2
Which listed expressions equal 1,999×2? Use distribution or compensation without full multiplication.
Question 2(b)
Find 12×125. Question 2(c)
Find 24×250. Question 2(f)
Find 300×15. Question 2(h)
Find 199×63. Question 2(i)
Find 128×35. Question 3
Give five products with an easy strategy. 32×25=8×100=800; 48×50=24×100=2,400; 99×37=3,700−37=3,663; 125×16=1,000×2=2,000; 75×12=75×(3×4)=900.
Answer Examples: 800, 2,400, 3,663, 2,000 and 900.
Question Neighbour explanation
What is added to move from 17×23 to 17×24 or 18×23? Increasing 24 from 23 adds one group of 17.
Increasing 17 to 18 adds one group of 23.
Answer Add 17 for 17×24; add 23 for 18×23.
Patterns, Estimation and Let Us Solve Textbook pages 87–91
Question Box puzzles
How are the coloured-box multiplication puzzles solved? Start at the ones column and test digits 0–9.
Carry to the next column, and keep equal colours equal within that problem.
Retain every assignment that matches all shown result digits.
Answer Some diagrams have more than one answer; the valid values are exactly those that satisfy every column and repeated-colour condition.
Question Estimate 1
Match 25×31 to the closest listed estimate. Round one or both factors to nearby friendly numbers.
Question Estimate 2
Match 132×19 to the closest listed estimate. Round one or both factors to nearby friendly numbers.
Question Estimate 3
Match 101×11 to the closest listed estimate. Round one or both factors to nearby friendly numbers.
Question Estimate 4
Match 248×49 to the closest listed estimate. Round one or both factors to nearby friendly numbers.
Question Estimate 5
Match 12×25 to the closest listed estimate. Round one or both factors to nearby friendly numbers.
Question King 1
Start with 5 coins and double daily for 7 days. Question King 2
Start with 3 coins and triple daily for 7 days. Question King 3
Start with 1 coin and multiply by 5 daily for 7 days. Answer 78,125 coins; Choice 3 is greatest.
Question Pattern a1
Find 16×22. Question Pattern a2
Find 32×44. Question Pattern b1
Find 6×16. Question Pattern b2
Find 24×16. Question Pattern b3
Find 24×64. Question Pattern b4
Find 12×16. Question Square 1
Find 1,111×1,111. Question Square 2
Find 45×45. Question Square 3
Find 55×55. Question Eleven 1
Find 11×54. Question Eleven 2
Find 11×82. Question Nines
Find 1,234×9+4. Question Adjacent pairs
Find the smallest and largest adjacent products in the displayed number grid. The smallest adjacent pair is 13 and 11: 13×11=143.
The largest adjacent pair is 75 and 62: 75×62=4,650.
Answer Smallest 143; largest 4,650.
Question Final 1
Mala buys 18 books at 3 for ₹150 and has ₹20 left. Find starting money. 18÷3=6 packs; 6×150=900.
900+20=920.
Question Final 2(a)
Find club income from 57 tickets at ₹115 and 3 team fees of ₹1,599. 57×115=6,555; 3×1,599=4,797.
6,555+4,797=11,352.
Question Final 2(b)
Find ground and food expenses ₹1,750 and ₹1,129. Question Final 3(a)
Ananya has 12 rows ahead and 17 behind. Count all rows including hers. Question Final 3(b)
There are 18 students right and 22 left of Ananya. Count her row. Question Final 3(c)
Find total students from 30 rows of 41. Question Final 4(a)
Find 67×78. Question Final 4(b)
Find 34×56. Question Final 4(c)
Find 45×263. Question Final 4(d)
Find 86×542. Question Final 4(e)
Find 432×107. Question Final 4(f)
Find 310×120. Question Final 5
Given 67×67=4,489, find 67×68. Add one more group of 67: 4,489+67=4,556.
Question Final 6
Given 99×100=9,900, find 99×99. Subtract one group of 99: 9,900−99=9,801.
← Chapter 5 Chapter 7 → Questions follow NCERT’s Maths Mela, Chapter 6 ↗ , checked on 2026-10-05. Use our original question summaries and worked answers alongside the questions in your textbook.
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