Question idli-mixtures
Viswanath mixes rice and urad dal in the ratio 6:3. Puneet uses 4:2. Would the mixtures have the same proportion?
Compare 6/3 and 4/2.
Both simplify to 2.
Answer
Yes. Both mixtures use 2 parts rice for every 1 part dal.
CLASS 8 · GANITA PRAKASH PART II · CHAPTER 3
Use ratios to mix and divide quantities, build pie charts, and solve direct and inverse proportion problems.
39 worked answers · short steps first, explanations when you need them
Textbook pages 56–60
Question idli-mixtures
Compare 6/3 and 4/2.
Both simplify to 2.
Yes. Both mixtures use 2 parts rice for every 1 part dal.
Question map-scale-conversion
1 cm on map represents 6,000,000 cm on the ground.
100,000 cm=1 km; 6,000,000÷100,000=60.
60 km. This is straight-line geographical distance, not road distance.
Question map-city-distance
Measure each line on the printed map with a ruler.
For each measured centimetre, multiply by 60 km.
Multiply each measured map length by 60 km per centimetre. The book labels this map ‘not to scale’, so ruler-based answers are only rough estimates; an accurate distance needs a true-scale map.
Question map-classroom-activity
At 1:50, 1 cm on the page represents 50 cm in the room.
Measure each room length and divide by 50 to find the drawing length in centimetres.
Mark the desk, board, fans and lights at measured positions.
This is a construction activity: for example, a 6 m wall is 600÷50=12 cm on the drawing. Your layout depends on your classroom measurements.
Question spice-ratio-scale
The chilli amount changes from 4 to 2, a scale factor of 1/2.
Multiply every ratio term by 1/2.
4 spoons coriander, 2 chillies, 1 spoon toor dal and 1/2 spoon methi; the ratio is 4:2:1:0.5.
Question purple-paint
5 parts correspond to 10 L, so 1 part=2 L.
Red=2×2=4 L; blue=3×2=6 L.
Total=4+6+10.
4 L red, 6 L blue; 20 L total.
Question concrete-mixture
Scale factor=3÷1=3.
Sand=1.5×3=4.5 bags; gravel=3×3=9 bags.
Total=3+4.5+9.
16.5 bags in total: 3 cement, 4.5 sand and 9 gravel.
Question divide-110-concrete
Total parts=1+1.5+3=5.5.
110÷5.5=20 units per part.
Amounts: 20, 30 and 60 units.
Cement 20 units, sand 30 units, gravel 60 units.
Question purple-paint-50ml
There are 10 parts altogether.
One part=50÷10=5 mL.
Red 10 mL, blue 15 mL and white 25 mL.
Question triangle-angle-ratio
Triangle angles total 180°.
There are 1+3+5=9 parts, so each part is 180÷9=20°.
20°, 60° and 100°.
Question cricket-session
Total parts=3+4+3+5=15.
One part=150÷15=10 minutes.
30 minutes warm-up/cool-down, 40 batting, 30 bowling and 50 fielding.
Question library-books
3 parts=288, so 1 part=96.
Hindi=2×96; English=1×96.
192 Hindi books and 96 English books.
Question coin-value
Total ratio parts=10, so 100÷10=10 coins per part.
Counts are 40, 30, 20 and 10.
Value=40×10+30×5+20×2+10×1.
₹600.
Question side-ratio-triangles
The side lengths can be 3,4,5 or 6,8,10 or 9,12,15.
These have the same ratio but different sizes.
No. They are similar in shape, but they need not be the same size, so they are not necessarily congruent.
Question impossible-triangle-ratio
For a triangle, the sum of the two shorter sides must be greater than the longest side.
Here 1+3=4, which is less than 5.
No. The triangle inequality fails.
Textbook pages 60–62
Question grade-pie-angles
A full circle is 360°. The total count is 40, so each student represents 360÷40=9°.
Multiply each grade count by 9°.
A:108°, B:90°, C:72°, D:54°, E:36°. The angles add to 360°.
Question season-pie
Winter count=360−90−120=150.
Since 360 people represent 360°, one person represents 1°.
Summer 90°, rainy 120°, winter 150°.
Question channel-pie
Multiply each percentage by 360°.
50%: 180°; 25%: 90°; 15%: 54°; 10%: 36°.
Entertainment 180°, sports 90°, news 54°, information 36°.
Question class-subject-pie
Count each subject and find the total responses.
For each subject, calculate count÷total×360°.
Use a protractor to draw the sectors and label them.
Answers depend on your class survey. The sector angles should total 360°.
Textbook pages 63–68
Question bricks-workers
18,000÷4,500=4 times as many bricks.
Workers must also be multiplied by 4: 5×4.
20 workers.
Question travel-time-speed
Distance=30×3=90 km.
Time=90÷60.
1.5 hours.
Question inverse-tables-classify
(i) products: 800,800,800,800.
(ii) products: 800,800,312.5,128.
(iii) products: 450 in every pair.
Tables (i) and (iii) show inverse proportion; table (ii) does not.
Question complete-inverse-table
Constant product=16×9=144.
For x=12, y=144÷12=12. For y=48, x=144÷48=3.
The missing values are y=12 and x=3.
Question road-workers-days
Total work=20×4=80 worker-days.
80÷10=8 days.
8 days.
Question tank-pumps
Pump-hours=2×18=36.
36÷4=9 hours.
9 hours.
Question food-students
Food amount=80×15=1,200 student-days.
1,200÷100=12 days.
12 days.
Question working-together-cutting
Ram rate=1 job/hour.
Shyam rate=1÷1.5=2/3 job/hour.
Together they do 1+2/3=5/3 jobs per hour.
Time for one job=1÷(5/3)=3/5 hour.
3/5 hour, or 36 minutes.
Question inverse-examples
For a fixed task, increasing the first quantity reduces the second: (i), (ii), (iv).
For (iii), (v), and (vi), both quantities increase together.
Inverse pairs:
(iv).
Question pencils-cost
Unit price=120÷24=₹5.
20×5=₹100.
₹100.
Question water-families
Total supply=20×6=120 family-days.
There are now 30 families, so 120÷30=4 days.
4 days, assuming daily use per family stays the same and there is no other water supply.
Question sleep-chart
One full ring represents 24 hours.
Hours asleep = shaded fraction × 24.
Match each ring from the smallest shaded part to the largest.
| Living being | Approximate shaded fraction | Sleep in 24 hours |
|---|---|---|
| Giraffe | about 1/10 | 2.5 h |
| Elephant | about 1/7 | 3.5 h |
| Child | 1/3 | 8 h |
| Dog | about 7/16 | 10.5 h |
| Cat | about 13/24 | 13 h |
| Monkey | 5/8 | 15 h |
| Snake | 3/4 | 18 h |
| Bat | 5/6 | 20 h |
Giraffe 2.5 h; elephant 3.5 h; child 8 h; dog 10.5 h; cat 13 h; monkey 15 h; snake 18 h; bat 20 h.
Question transport-pie
Known sectors: bus 120°, walk 90°, cycle 60°, two-wheeler 60°.
Car=360°−(120°+90°+60°+60°)=30°; car fraction=30/360=1/12.
Total=18×12=216; cycle and two-wheeler are equal (60° each).
| Mode shown in chart | Sector angle |
|---|---|
| Bus | 120° |
| Walk | 90° |
| Cycle | 60° |
| Two-wheeler | 60° |
| Car | 30° (remaining angle) |
| Taxi | Not shown |
Bus is most common; car=1/12; total=216 children; taxi=0 in the chart; cycle and two-wheeler are equal.
Question fence-workers
Total work=3×4=12 worker-days.
12÷4=3 days.
3 days, assuming each worker paints at the same rate and the whole fence can be divided among them.
Question tanks-same-pump
The pump fills 2 tanks in 6 hours, or 1/3 tank per hour.
5÷(1/3)=15 hours.
15 hours, assuming the pump rate remains constant and the tanks are filled one after another or continuously at that rate.
Question chair-rows
Total chairs=25×12=300.
300÷20=15.
15 rows.
Question school-period-length
Total class time=8×45=360 minutes.
360÷9=40 minutes.
40 minutes per period.
Question two-pumps-rates
Small-pump rate=1/3 tank/hour; large-pump rate=1/2 tank/hour.
Combined rate=1/3+1/2=5/6 tank/hour.
Time=1÷(5/6)=6/5 hours.
1.2 hours, or 1 hour 12 minutes.
Question factory-machines
Machine-days=42×63=2,646.
2,646÷54=49.
49 machines.
Question car-speed
Distance=60×2=120 km.
Time=120÷80=1.5 hours.
1.5 hours.