Question Quilt lace
Which lace roll covers the whole quilt border?
The border totals 50 units.
Answer
The 50-unit green lace.
CLASS 5 · MATHS MELA · CHAPTER 11
Measure perimeter and area with tiles and grids, compare shapes and apply rectangle and square formulas to practical objects.
46 worked answers · short steps first, explanations when you need them
Textbook pages 142–143
Question Quilt lace
The border totals 50 units.
The 50-unit green lace.
Question Two laces
50÷2=25.
25 units of each colour.
Question 1(a)
5×4=20.
20 cm.
Question 1(b)
All six triangle sides lie on the outside.
6×5=30.
30 cm.
Question 2(a)
2(L+B)=26, so L+B=13.
Examples: 6 cm×7 cm and 5 cm×8 cm.
Question 2(b)
2(L+B)=18, so L+B=9.
Examples: 4 cm×5 cm and 3 cm×6 cm.
Question Rug patches
Count 4 rows and 14 patches per row.
4×14=56.
56 patches.
Question Tiling shapes
Triangles, squares and rectangles meet edge-to-edge.
Circles leave curved gaps.
Triangles, squares and rectangles tile; circles do not.
Question Table 1
The table has 10 square regions, each split into 2 triangles.
10×2=20.
20 triangle units.
Question Table 3
Count 2 rows of 5.
10 square units.
Question Table 4
Count 4 rows of 5 small rectangles.
20 rectangle units.
Question Circles
Touching circles leave curved spaces between them.
No, circles alone do not tile the plane.
Question Real objects
Arrange notebooks, lunch boxes, pencil boxes or textbooks edge-to-edge.
Record whether gaps or overlaps remain.
Rectangular objects can cover it if their dimensions fit the table in whole rows and columns; the observed answer depends on the objects and table.
Textbook pages 144–146
Question Desk area
There are 9 columns and 6 rows.
9×6=54.
54 square units.
Question Green triangles
One green triangle is half a grid square.
54×2=108.
108 green triangles.
Question Red triangles
The red right triangle has base and height 3 units, so its area is 3×3÷2=4.5 square units.
54÷4.5=12.
12 red triangles.
Question Blue squares
One blue tile equals one grid square.
54 blue squares.
Question Rectangles A–C
A=3×4=12; B=2×4=8; C=2×5=10.
A has the largest area; A>C>B.
Question Garden A
It covers 2 columns×5 rows.
10 cm².
Question Garden B
It covers 4 columns×3 rows.
12 cm².
Question Garden comparison
12−10=2.
Garden B by 2 cm².
Question Palm
Count fully covered squares.
Combine partly covered squares into approximate whole squares.
Student-specific; approximate area=full squares+about half of the boundary squares.
Question Leaves
Use the same full-square and partial-square method for every leaf.
The leaf with the greatest estimated square count is largest; the least count is smallest.
Textbook pages 147–150
Question Mat (a)
Area=5×2=10.
Perimeter=2(5+2)=14.
Area 10 square units; perimeter 14 units.
Question Mat (b)
Area=4×3=12.
Perimeter=2(4+3)=14.
Area 12 square units; perimeter 14 units.
Question Trisha claim
The two mats have areas 10 and 12 but both perimeters are 14.
No.
Question Explore 1 · same area
Count shaded unit squares.
Shapes (a), (c), (d) and (f) each contain 12 squares.
(a), (c), (d) and (f), each area 12 cm².
Question Explore 1 · perimeters
(a), a 6×2 rectangle, has perimeter 16.
(c) and (d), 3×4 and 4×3 rectangles, have perimeter 14.
(f), a 1×12 strip, has perimeter 26.
Perimeters are 16, 14, 14 and 26 cm respectively.
Question Explore 2 · first group
For each shape use P=4n−2e, where n is squares and e is shared edges.
Shapes (a) and (b), each with perimeter 12 cm.
Question Explore 2 · second group
Count outside edges for the cross, L and strip.
Shapes (c), (d) and (e), each with perimeter 16 cm.
Question Explore 2 · areas
Count shaded unit squares in each.
Each shape has area 7 cm².
Question Same area drawing
Given area=2×9=18 cm², perimeter=22 cm.
A 3×6 rectangle also has area 18 and perimeter 18.
A 1×18 rectangle has area 18 and perimeter 38.
Examples: 3×6 and 1×18; all have area 18 cm² but different perimeters.
Question Square and triangle
Square area=3×3=9.
Triangle base=6 and height=3, so area=6×3÷2=9.
No; their areas are equal at 9 cm².
Question Patchwork
6×4=24.
24 patches.
Textbook pages 151–154
Question Square example
Area=5×5=25.
Perimeter=4×5=20.
25 cm² and 20 cm.
Question Classroom
Measure length L and breadth B in metres.
Area=L×B; perimeter=2(L+B).
Student-specific; report L×B m² and 2(L+B) m.
Question 2(a)
Area=6×6=36.
Perimeter=2(6+6)=24.
36 cm²; 24 cm.
Question 2(b)
Area=4×7=28.
Perimeter=2(4+7)=22.
28 cm²; 22 cm.
Question 2(c)
Area=12×4=48.
Perimeter=2(12+4)=32.
48 cm²; 32 cm.
Question 2(d)
Area=3×3=9.
Perimeter=2(3+3)=12.
9 cm²; 12 cm.
Question 2(e)
Area=6×5=30.
Perimeter=2(6+5)=22.
30 cm²; 22 cm.
Question Objects table
For each object record length L and breadth B in the same unit.
Calculate L×B and 2(L+B).
Answers depend on the measured objects; include dimensions, square units for area and length units for perimeter.
Question 4
42×34=42×30+42×4=1,260+168.
1,428 m².
Question 5
64÷16=4.
4 m.
Question 6
Total height=6+12=18 cm.
Area=32×18.
576 cm².
Question Tile game
An isolated tile adds 4 edges.
For every edge it shares with the existing figure, subtract 2 from that increase.
New perimeter=old perimeter+4−2×shared edges; the first player to make 24 wins.