Question 1
A tortoise walks 1/4 km per hour. How far does it walk in 3 hours?
Multiply the hourly distance by 3.
3×1/4=3/4.
Answer
3/4 km.
CLASS 7 · GANITA PRAKASH PART I · CHAPTER 8
Multiply and divide fractions, interpret rates and solve fraction problems with pictures and clear steps.
45 worked answers · short steps first, explanations when you need them
Textbook pages 174–185
Question 1
Multiply the hourly distance by 3.
3×1/4=3/4.
3/4 km.
Question 2
Multiply 3 by each time fraction.
3×1/5=3/5 km; 3×2/5=6/5=1 1/5 km.
Question 3
Add five equal shares, or multiply 5×2/3.
10/3=3 1/3 acres.
Question 4
Convert 1 1/4 to 5/4.
Multiply by the hourly rate: 5/4×8.
₹10.
Question 5
Multiply 1/2 by the number of days.
7 days: 7/2=3 1/2 glasses. January: 31/2=15 1/2 glasses.
Question 6
Divide 1 km into 8 equal daily amounts.
Multiply the daily amount by 5.
1/8 km per day; 5/8 km in five days.
Question 7
Divide 5 by 3.
Multiply the weekly share by 4.
5/3=1 2/3 litres per week; 20/3=6 2/3 litres in four weeks.
Question 8
Monday to Thursday has three daily intervals.
Multiply 3×5/6=15/6=2 1/2 hours.
2 1/2 hours later, so approximately 12:30 am on Friday.
Question 9
Multiply the whole number by the numerator, then divide by the denominator.
21/5=4 1/5; 4/3=1 1/3; 54/7=7 5/7; 78/11=7 1/11.
Question 10
Multiply the numerators and multiply the denominators.
1/15; 1/12; 1/10; 1/30; 1/216.
Question 11
Multiply across, then reduce common factors.
8/15; 2/12=1/6; 3/10; 12/30=2/5.
Question 12
Multiply numerators and denominators.
Cancel common factors before multiplying when possible.
(a/b)(c/d)=ac/bd. 5/12×7/18=35/216; 12/7×5/24=5/14.
Question 13
Multiply rate by time.
15/4=3 3/4 km; 1/8 km.
Question 14
Multiplying by a factor above 1 enlarges a positive number.
Multiplying by a positive factor below 1 makes it smaller.
Both >1: product exceeds both. Both between 0 and 1: product is below both. One below 1 and one above 1: the product lies between the two.
Question 15
The numerator and denominator products are unchanged when factors are swapped.
No: a/b×c/d=c/d×a/b.
Textbook pages 186–193
Question 1
Find the number that multiplies c/d to make 1.
d/c, because (c/d)(d/c)=1.
Question 2
Keep the first fraction, change division to multiplication, and flip the divisor.
3/2; 9/2; 2/5; 10/9.
Question 3
If x÷(c/d)=a/b, then (c/d)×(a/b)=x.
Multiplying by d/c reverses multiplication by c/d.
a/b÷c/d=(a/b)×(d/c)=ad/bc, provided c≠0.
Question 4
Divide by 1/4 by multiplying by 4.
Yes. 6÷1/4=24 and 1/8÷1/4=1/2; both exceed their dividends.
Question 5
Multiply 7/10 by each time fraction.
For a full tank, divide 1 by the rate 7/10.
7/30; 14/30=7/15; 21/40; 49/100 of the tank. Full tank: 1÷7/10=10/7=1 3/7 hours.
Question 6
After the road, 5/6 remains.
Krishna gets 1/2×5/6; Bora gets 1/3×5/6.
Subtract both gifts from 5/6.
Krishna: 5/12; Bora: 5/18; Somu keeps 5/36 of the original plot.
Question 7
Convert to improper fractions: 15/4 and 48/5.
Multiply side lengths.
(15/4)(48/5)=36 square feet.
Question 8
Four saplings create three equal gaps.
Multiply 3×3/4.
9/4=2 1/4 m.
Question 9
12/15×500=400 g.
Convert 4 kg to 4,000 g; multiply by 3/20.
3/20 of 4 kg=600 g, so it is heavier.
Question 10
Their individual rates are 1, 2, 4 and 5 cisterns per day.
Add rates.
1+2+4+5=12 cisterns per day.
Question 11
Count equal parts in the whole square and count shaded parts.
Reduce the resulting fraction.
Figure (a): 3/8; figure (b): 1/16.
Question 12
For each, keep the first number, change division to multiplication, and flip the second number.
Simplify each product.
3×9/7=27/7; 14/4×1/2=7/4; 2/3×3/2=1; 14/6×3/7=1; 4/3×4/3=16/9; 7/4×7=49/4; 4×15/4=15; 1/5×9=9/5; 1/6×12/11=2/11; 11/3×8/11=8/3=2 2/3.
Textbook pages 190–197
Question 1
Divide the total amount equally among 5 cups.
1/4÷5=1/4×1/5.
1/20 litre per cup.
Question 2
One brick area=(1/5)(1/5)=1/25.
Total area=15/2.
Divide total area by area per brick.
(15/2)÷(1/25)=375/2=187 1/2 square-brick areas. This shows the given area is not an exact whole number of such bricks; 188 bricks would be needed to cover it completely.
Question 3
Together they fill 12 cisterns in one day.
Time for one cistern is the reciprocal rate.
1/12 day.
Question 4
Number of bags=total lace÷lace per bag.
8÷1/4=8×4.
32 bags.
Question 5
Share 1/2 m equally among 8.
1/2÷8=1/16 m per badge.
Question 6
Divide flour available by flour per loaf.
5÷1/6=30 loaves.
Question 7
Six is half of twelve, so use half the flour.
1/8 kg.
Question 8
Dividing 1 by 1/n gives n.
Add the resulting whole numbers.
6+10+13+9+2=40.
Question 9
Read fraction=1/5+3/10=1/2.
Remaining fraction=1/2.
Find half of 400.
200 pages remain.
Question 10
Convert 2 3/4=11/4.
Multiply 16×11/4.
44 km.
Question 11
Subtract 1/2 from 5 1/6.
Use sixths: 31/6−3/6=28/6.
4 2/3 hours.
Question 12
Remaining fraction=1−4/5=1/5.
Divide by 3.
1/5÷3=1/15 of the whole cake each.
Question 13
Multiply the branch fractions along each route and add routes reaching the same food.
Mango tree: 29/32; sugarcane field: 3/32.
Question 14
Rewrite each factor as (k−1)/k.
The product is (1/2)(2/3)(3/4)…((n−1)/n); cancel matching factors.
1/n. For n=2,3,5,10 the values are 1/2, 1/3, 1/5, 1/10.
Question 15
Count the equal smallest regions in the whole and the shaded set.
The figure’s exact subdivision is image-based.
3/32 of the whole square.
Question activity-dramma
Multiply the fractions: (3/4)(2/3)(1/2)(1/4)(1/16)(1/5).
Cancel common factors, then convert the fraction of a dramma to cowries.
The product is 1/1,280 dramma. Since 1 dramma is 1,280 cowries, the donation is 1 cowrie.
Question activity-coin-conversion
One pana is divided into 30 cowries, so one cowrie is 1/30 pana.
One pana is 1/4 of a dramma, and one dramma is 1/12 of a gold dinar. Multiply these fractions.
1 cowrie=1/30 pana=(1/30)(1/4)(1/12)=1/1,440 gold dinar.
Question 9-product
56/45>1 and 70/67>1.
Multiplying a positive number by a factor greater than 1 makes it larger.
The product is greater than each factor and greater than 1. Choose (a), (c), and (e).