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CLASS 7 · GANITA PRAKASH PART I · CHAPTER 4

Expressions using Letter-Numbers

Use letters to describe quantities, evaluate expressions, combine like terms and explain patterns.

47 worked answersAll 1 exercise setsAll 15 end-of-chapter questions

What you will learn

  • Translate everyday relationships into algebraic expressions.
  • Substitute values and simplify expressions using brackets and like terms.
  • Use algebra to explain number, calendar and shape patterns.

47 worked answers · short steps first, explanations when you need them

4.1 Representing relationships with letters

Textbook pages 82–85

Question 1

Shabnam is three years older than Aftab. Write a rule using a for Aftab’s age. Find Shabnam’s age when Aftab is 18 and when a=23.

Steps only

Add 3 to Aftab’s age: s=a+3.

For a=18, s=18+3; for a=23, s=23+3.

Answer

s=a+3; if a=18, Shabnam is 21; if a=23, she is 26 years old.

Question 2

Aftab is three years younger than Shabnam. Write the rule and find his age if Shabnam is 20.

Steps only

Subtract 3 from Shabnam’s age: a=s−3.

Substitute s=20.

Answer

a=s−3=20−3=17 years.

Question 3

Each L shape uses two matchsticks. How many are needed for 5, 7 and 45 Ls? Give a rule for n Ls.

Steps only

Multiply the number of Ls by 2.

Answer

5→10 sticks; 7→14; 45→90; general rule: 2n sticks.

Question 4

Coconuts cost ₹35 each and jaggery costs ₹60 per kg. Find the cost for 10 coconuts and 5 kg jaggery, for 8 coconuts and 9 kg jaggery, and for 7 coconuts and 4 kg jaggery; then write the general rule.

Steps only

Cost=35c+60j.

For 8 coconuts and 9 kg: 35×8+60×9.

For 7 coconuts and 4 kg: 35×7+60×4.

Answer

The rule is 35c+60j rupees. The three totals are ₹650, ₹820 and ₹485.

Question 5

Write perimeter formulas for a square, an equilateral triangle, a regular pentagon and a regular hexagon when each side has length a. Also find the square’s perimeter when a=7 cm.

Steps only

Count the equal sides in each shape.

Multiply that count by a.

Answer

Square: 4a; triangle: 3a; pentagon: 5a; hexagon: 6a. For a=7 cm, the square perimeter is 28 cm.

Question 6

A 20 m pipe is joined to a second pipe of k metres. Give the total length.

Steps only

Add the two lengths.

Answer

20+k metres.

Question 7

Find the amount for note counts (3,5,6), (6,4,3), (8,4,z), and (x,y,z) for ₹100, ₹20 and ₹5 notes respectively.

Steps only

Multiply each note count by its denomination.

Add the three values.

Answer

₹430; ₹695; ₹880+5z; general amount =100x+20y+5z rupees.

Question 8

A mill takes 10 seconds to start, then 8 seconds per kg to grind y kg. Which expression gives the total time?

Steps only

Starting time is paid once: 10 seconds.

Grinding time is 8y seconds.

Answer

10+8y seconds (choice d).

Question 9

Use n for a number. Write: 5 more; 4 less; 2 less than 13 times; 13 less than twice the number.

Steps only

Translate “more” as addition and “less than” as subtraction after the stated amount.

Answer

n+5; n−4; 13n−2; 2n−13.

Question 10

Give situations represented by 8x+3y and 15j−2k.

Steps only

For 8x+3y, combine two purchases with different prices.

For 15j−2k, start with a repeated production amount and subtract losses.

Answer

Example: 8x is the cost of x items at ₹8 each and 3y the cost of y items at ₹3 each. For the second, make 15 chairs per day for j days, then subtract 2 damaged chairs on each of k days.

Question 11

A 2×3 calendar block has bottom-middle date w. Write the dates in the other five cells.

Steps only

Dates change by 1 horizontally and by 7 vertically.

Move from w left/right and one week up.

Answer

Top row: w−8, w−7, w−6. Bottom row: w−1, w, w+1.

4.2 Revisiting arithmetic expressions

Textbook pages 85–86

Question 1

Evaluate 23−10×2; 83+28−13+32; 34−14+20; 42+15−(8−7); 68−(18+13); 7×4+9×6; 20+8×(16−6).

Steps only

Do multiplication and brackets first.

For addition and subtraction, regroup convenient positive and negative terms.

Answer

3; 130; 40; 56; 37; 82; 100.

Question 2

Write the nth term of 4,8,12,16,… and find the third and 29th terms.

Steps only

Every term is 4 times its position.

Answer

nth term=4n; third term=12; 29th term=116.

Question 3

Find 7k when k=4 and 5m+3 when m=2.

Steps only

Replace each letter with its given number.

Multiply before adding.

Answer

7(4)=28; 5(2)+3=13.

Question 4

For each claim, test the substitution and correct any errors: (a=−4) 10−a=6; (d=6) 3d=36; (s=7) 3s−2=15; (r=8) 2r+1=29; (j=5) 2j=10; (m=−6) 3(m+1)=19; (f=3,g=1) 2f−2g=2; (t=4,b=3) 2t+b=24; (h=5,n=6) h−(3−n)=4.

Steps only

Substitute first, keeping the brackets and signs.

Evaluate multiplication and then addition/subtraction.

Answer

(a)14, false; (b)18, false; (c)19, false; (d)17, false; (e)10, true; (f)−15, false; (g)4, false; (h)11, false; (i)8, false.

4.3–4.4 Multiplication notation and simplification

Textbook pages 86–95

Question 1

Simplify p+p+p+p; p+p+p+q; p+q+p−q; p−q+p−q; p+q−p+q; p+q−(p+q); p−q−p−q.

Steps only

Collect coefficients of p and q separately.

When removing a bracket preceded by minus, reverse both signs inside.

Answer

4p; 3p+q; 2p; 2p−2q; 2q; 0; −2q.

Question 2

Simplify 2d−d−d−d; 2d−d−d−c; 2d−d−(d−c); 2d−(d−d)−c; 2d−d−c−c.

Steps only

Remove brackets carefully, then combine coefficients.

Answer

−d; −c; c; 2d−c; d−2c.

Question 3

A rectangle has length l and breadth b. Simplify l+b+l+b.

Steps only

Group the two lengths and two breadths.

Answer

2l+2b.

Question 4

A shop sells 5, 3 and 10 pencils at price c each, and 4, 6 and 1 erasers at price d each. Simplify total revenue.

Steps only

Pencils: (5+3+10)c=18c.

Erasers: (4+6+1)d=11d.

Answer

18c+11d. If c=₹50, pencil revenue is ₹900.

Question 5

A large rectangle of height v is split into widths 4 and 3. Express its area both ways. Another rectangle has height n and widths 12 and 4 removed.

Steps only

Whole width 4+3=7 gives area 7v; small areas give 4v+3v.

For the second, subtract the 4n strip from 12n.

Answer

4v+3v=7v; 12n−4n=8n.

Question 6

Chair rental costs ₹40 and returns ₹6 as deposit; table rental costs ₹75 and returns ₹10. Simplify the net amount for x chairs and y tables.

Steps only

Net chair cost: (40−6)x.

Net table cost: (75−10)y.

Answer

(40x+75y)−(6x+10y)=34x+65y.

Question 7

Three rounds have scores 7p−3q, 8p−4q, 6p−2q. Find each score when p=4,q=1, total score, and how much more 23p−7q is than their total.

Steps only

Substitute p=4,q=1 in each round.

Combine like terms for the total, then subtract.

Answer

Round scores: 25, 28, 22; total=21p−9q=75 points. (23p−7q)−(21p−9q)=2p+2q; at p=4,q=1, this is 10 points.

Question 8

Simplify 4(x+y)−y. Are 5u and 5+u equal? Are 10y−3 and 10(y−3) equal?

Steps only

Distribute the multiplier across terms inside brackets.

Use a value such as u=2 to test whether two expressions are identical.

Answer

4x+3y. 5u and 5+u are not equal in general (at u=2 they are 10 and 7). 10y−3 and 10(y−3) are not equal in general; at y=2 they are 17 and −10.

Question 9

The three printed arrays contain repeated terms. Simplify their totals.

Steps only

Collect like terms within each picture.

For the first, terms are 5y,x,x,5y,−6,2.

For the other arrays, count each repeated symbol.

Answer

  • (i) 10y+2x−4;
  • (ii) 8p+12q+2;
  • (iii) −20g+60k.

Question 11

Look at the corrected simplest forms in the mistake-check table. Is the number of terms always the same as the number of different letters?

Steps only

Count each separated addend or subtrahend as a term.

Check examples with and without a constant term.

Answer

No. Each different letter usually gives one variable term, and there may also be one constant term: 6p+12 has 2 terms but 1 letter; 3a+2b has 2 terms and 2 letters; −b has 1 term and 1 letter.

Question 10

Correct: 3a+2b→5; 3b−2b→0; 6(p+2)→6p+8; (4x+3y)−(3x+4y)→x+5; 5−(2−6z)→3−6z; 2+(x+3)→2x−6; 2y+(3y−6)→−y+6; 7p−p+5q−2q→7p+3q; 5(2w+3x+4w)→10w+15x+20w; 3j+6k+9h+12→3(j+2k+3h+4); 4(2r+3s+5)→−20−8r−12s.

Steps only

Distribute any outside factor.

For a minus before parentheses, change every sign inside.

Combine like terms only.

Answer

Correct forms in order: 3a+2b; b; 6p+12; x−y; 3+6z; x+5; 5y−6; 6p+3q; 30w+15x; 3j+6k+9h+12; 8r+12s+20.

4.5 Patterns and algebraic relationships

Textbook pages 95–105

Question 1

A number machine doubles its first input a and subtracts its second input b. Write its formula and find the outputs for (5,2), (8,8), (15,1), (7,9) and (10,11).

Steps only

Write the rule as 2a−b.

Substitute each ordered pair, keeping the first number as a and the second as b.

Answer

2a−b gives 8, 15, 7, 10 and 8 respectively.

Question 1b

For the first pictured machine, the input-output pairs are (5,2)→5, (8,1)→7, (9,11)→18 and (10,10)→18. For the second, (4,1)→5, (6,0)→1 and (3,2)→7. Find each rule and write the output for its final inputs (a,b).

Steps only

Test a+b−2 on each first-machine pair.

Test ab+1 on each second-machine pair.

Substitute the final symbolic inputs.

Answer

First rule: a+b−2, so the final output is a+b−2. Second rule: ab+1, so the final output is ab+1. For the other shown inputs, the outputs are 8 and 31 respectively.

Question 1c

Give one valid rule for a two-input machine and show three input-output examples.

Steps only

Choose an easy rule, such as adding the inputs and then adding 1.

Use different input pairs and apply the same rule each time.

Answer

Example rule: a+b+1. Inputs (2,3), (5,1), and (0,4) give outputs 6, 7, and 5.

Question 2

In a repeating A,B,C design, give the nth positions for each design and find the designs at positions 99, 122 and 148.

Steps only

C occurs at multiples of 3; B is one less; A is two less.

Use the remainder after division by 3.

Answer

A: 3n−2; B: 3n−1; C: 3n. Position 99: C; 122: B; 148: A.

Question 3

Show that the two diagonal sums in any 2×2 calendar block are equal.

Steps only

Let the upper-left date be a.

The block is a, a+1, a+7, a+8.

Both diagonal sums simplify to 2a+8.

Answer

a+(a+8)=(a+1)+(a+7)=2a+8.

Question 4

In a 3×3 calendar cross, the centre date is a. Find the sum of the centre and its four direct neighbours.

Steps only

The dates above, below, left and right are a−7, a+7, a−1 and a+1.

Add these and the centre a.

Answer

(a−7)+(a−1)+a+(a+1)+(a+7)=5a.

Question 4b

A row of joined triangles uses 3 matchsticks in Step 1 and adds 2 matchsticks at every new step. Find the counts for Steps 5, 33, 84 and 108, then give a rule for Step y.

Steps only

Start with 3 sticks.

There are y−1 increases of 2 sticks.

Use 3+2(y−1)=2y+1.

Answer

Step 5: 11; Step 33: 67; Step 84: 169; Step 108: 217. General rule: 2y+1 matchsticks.

Question 5

At step y, the pattern has y horizontal sticks and y+1 diagonal sticks. Find the total and values at steps 3 and 4.

Steps only

Add the two orientation counts.

Answer

Horizontal=y; diagonal=y+1; total=2y+1. Step 3: 3 horizontal, 4 diagonal, 7 total. Step 4: 4 horizontal, 5 diagonal, 9 total.

Question 6

Jowar roti costs ₹30 per plate and pulao ₹20. For x and y plates respectively, choose the expression for total earnings.

Steps only

Multiply each price by its own quantity.

Answer

30x+20y (option a).

Question 7

p customers buy only champak, q only marigold, and r buy both. One flag is given to every customer. How many flags?

Steps only

Each group is already a count of customers.

Add the three disjoint groups once each.

Answer

p+q+r flags (option a).

Question 8

A snail climbs u cm each day and slips d cm each night for 10 days and nights. Write its net movement and interpret d>u.

Steps only

One day-night cycle changes position by u−d.

Multiply the change by 10 cycles.

Answer

10(u−d) cm. If d>u, the net change is downward each cycle.

Question 9

Radha cycles 5 km daily in week 1, then increases her daily distance by z each new week. How far in total over three weeks?

Steps only

Daily distances are 5, 5+z, 5+2z.

Each applies for seven days.

Answer

7[5+(5+z)+(5+2z)]=105+21z km.

Question 10

Starting at w+2, follow each arrow path in the diagram: (a) subtract 5, then multiply by 3; (b) add 3, then multiply by 4; (c) subtract 8, then subtract 4; (d) subtract 4, then multiply by 3. Find every intermediate and final expression.

Steps only

Apply each operation in the arrow’s order.

For multiplication, put parentheses around the entire current expression.

Answer

(a) w+2−5=w−3; 3(w−3)=3w−9. (b) w+2+3=w+5; 4(w+5)=4w+20. (c) w+2−8=w−6; w−6−4=w−10. (d) w+2−4=w−2; 3(w−2)=3w−6.

Question 11

A train route has three equally spaced intermediate stations. Each of four travel legs takes t minutes and each station stop is 2 minutes. Find the expression and value for t=4.

Steps only

There are four travel intervals and three stops.

Total=4t+3(2).

Substitute t=4.

Answer

4t+6 minutes; at t=4, 22 minutes.

Question 12

Simplify: (a) 3a+9b−6+8a−4b−7a+16; (b) 3(3a−3b)−8a−4b−16; (c) 2(2x−3)+8x+12; (d) 8x−(2x−3)+12; (e) 8h−(5+7h)+9; (f) 23+4(6m−3n)−8n−3m−18.

Steps only

Expand brackets, reversing signs after a leading minus.

Collect coefficients of matching variables and constants.

Answer

(a) 4a+5b+10; (b) a−13b−16; (c) 12x+6; (d) 6x+15; (e) h+4; (f) 5+21m−20n.

Question 13

Add each pair: (a) 4d−7c+9 and 8c−11+9d; (b) −6f+19−8s and −23+13f+12s; (c) 8d−14c+9 and 16c−(11+9d); (d) 6f−20+8s and 23−13f−12s; (e) 13m−12n and 12n−13m; (f) −26m+24n and 26m−24n.

Steps only

Remove parentheses and add coefficients of like terms.

Answer

(a) 13d+c−2; (b) 7f+4s−4; (c) 2c−d−2; (d) −7f−4s+3; (e) 0; (f) 0.

Question 14

Subtract the first expression from the second in each pair: (a) 9a−6b+14 from 6a+9b−18; (b) −15x+13−9y from 7y−10+3x; (c) 17g+9−7h from 11−10g+3h; (d) 9a−6b+14 from 6a−(9b+18); (e) 10x+2+10y from −3y+8−3x; (f) 8g+4h−10 from 7h−8g+20.

Steps only

Write (second)−(first).

Distribute the minus sign across every term of the expression being subtracted.

Collect like terms.

Answer

(a) −3a+15b−32; (b) 18x+16y−23; (c) 10h−27g+2; (d) −3a−3b−32; (e) −13x−13y+6; (f) 3h−16g+30.

Question 15

A rope is folded r times and cut once. Give the piece count. A row of w joined squares uses how many matchsticks?

Steps only

Rope pieces follow the pattern folds+2.

For squares, the first needs 4 sticks and each added square shares one side, adding 3.

Answer

Rope: r+2 pieces (12 for 10 folds). Squares: 4+3(w−1)=3w+1 sticks (31 for 10 squares).

Question 16

The colour cycle is red, yellow, green, yellow, repeating. Find positions 90, 190 and 343 and give position formulas.

Steps only

Use the remainder modulo 4.

Red is first; green is third; yellow occupies the even positions.

Answer

90: yellow; 190: yellow; 343: green. Red positions: 4n−3; green: 4n−1; yellow: 2n.

Question 17

A square pattern adds four squares at each step, starting with five. Find the count at steps 4, 10 and 50, the general rule, and the formula for vertices.

Steps only

Square count=5+4(y−1)=4y+1.

Use the pattern’s vertex-count rule: 16y+4.

Answer

Step 4: 17 squares; step 10: 41; step 50: 201. Square formula: 4y+1; vertex formula: 16y+4.

Question 18

For an endless grid filled left-to-right with consecutive integers in four columns: give each column formula; locate 124, 147 and 201 by row and column; give the entry in row r, column c; and describe the repeating columns containing multiples of 3.

Steps only

Each row contains four consecutive numbers, so use 4(r−1)+c.

Divide by 4; a remainder 0 means column 4 of that quotient row.

Check the first rows to see the repeating column pattern.

Answer

Column formulas: 4(r−1)+1, +2, +3, +4. 124 is row 31, column 4; 147 is row 37, column 3; 201 is row 51, column 1. General entry: 4(r−1)+c. Multiples of 3 occur in columns 3, 2, 1, 4, repeating.

Questions follow NCERT’s Ganita Prakash Part I, Chapter 4 ↗, checked on 2026-10-06. Use our original question summaries and worked answers alongside the questions in your textbook.

Diagrams are drawn from mathematical rules. Learnivelle is not affiliated with NCERT.

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