Question 1
What are the y- and z-coordinates of a point on the x-axis?
P = (x, 0, 0)
Answer
y = 0 and z = 0.
CLASS 11 · MATHEMATICS · CHAPTER 11
Locate points in space, calculate distances and use coordinate relationships. Start with the short working and open the explanation for each method.
29 worked answers · short steps first, explanations when you need them
Textbook pages 211
Question 1
P = (x, 0, 0)
y = 0 and z = 0.
Question 2
P = (x, 0, z)
y = 0.
Question 3 · point 1
Signs of (x, y, z): (+, +, +)
Octant I.
Question 3 · point 2
Signs of (x, y, z): (+, −, +)
Octant IV.
Question 3 · point 3
Signs of (x, y, z): (+, −, −)
Octant VIII.
Question 3 · point 4
Signs of (x, y, z): (+, +, −)
Octant V.
Question 3 · point 5
Signs of (x, y, z): (−, +, −)
Octant VI.
Question 3 · point 6
Signs of (x, y, z): (−, +, +)
Octant II.
Question 3 · point 7
Signs of (x, y, z): (−, −, +)
Octant III.
Question 3 · point 8
Signs of (x, y, z): (−, −, −)
Octant VII.
Question 4(i)
x-axis and y-axis ⇒ XY-plane
XY-plane.
Question 4(ii)
P = (x, y, 0)
(x, y, 0).
Question 4(iii)
2 × 2 × 2 = 8
8 octants.
Textbook pages 213
Question 1(i)
d² = (x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²
= (2)² + (0)² + (-4)²
= 20
d = 2√5
2√5 units.
Question 1(ii)
d² = (x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²
= (5)² + (-3)² + (-3)²
= 43
d = √43
√43 units.
Question 1(iii)
d² = (x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²
= (2)² + (-6)² + (8)²
= 104
d = 2√26
2√26 units.
Question 1(iv)
d² = (x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²
= (-4)² + (2)² + (0)²
= 20
d = 2√5
2√5 units.
Question 2
PQ = √14
QR = 2√14
PR = 3√14
PQ + QR = PR
The points are collinear, with Q between P and R.
Question 3(i)
AB² = 1 + 1 + 16 = 18
BC² = 9 + 9 + 0 = 18
AC² = 16 + 4 + 16 = 36
AB = BC = 3√2; the triangle is isosceles.
Question 3(ii)
AB² = 18; BC² = 18; AC² = 36
AB² + BC² = AC²
The angle at B is 90°.
Question 3(iii)
Midpoint of AC = (3/2, −5/2, 9/2)
Midpoint of BD = (3/2, −5/2, 9/2)
ABCD is a parallelogram.
Question 4
(x − 1)² + (y − 2)² + (z − 3)² = (x − 3)² + (y − 2)² + (z + 1)²
4x − 8z = 0
x − 2z = 0
x − 2z = 0.
Question 5
PA + PB = 10
PB² − PA² = 16x
PB − PA = 8x/5
PA = 5 − 4x/5
(x − 4)² + y² + z² = (5 − 4x/5)²
x²/25 + (y² + z²)/9 = 1
x²/25 + y²/9 + z²/9 = 1.
Textbook pages 215
Question 1
A + C = B + D
D = A + C − B
= (1, −2, 8)
D = (1, −2, 8).
Question 2 · median from A
Opposite-side midpoint = (3, 2, 0)
Median² = 49
Median = 7
7 units.
Question 2 · median from B
Opposite-side midpoint = (3, 0, 3)
Median² = 34
Median = √34
√34 units.
Question 2 · median from C
Opposite-side midpoint = (0, 2, 3)
Median² = 49
Median = 7
7 units.
Question 3
2a − 4 + 8 = 0 ⇒ a = −2
2 + 3b + 14 = 0 ⇒ b = −16/3
6 − 10 + 2c = 0 ⇒ c = 2
a = −2; b = −16/3; c = 2.
Question 4
(x − 3)² + (y − 4)² + (z − 5)² + (x + 1)² + (y − 3)² + (z + 7)² = k²
2x² + 2y² + 2z² − 4x − 14y + 4z + 109 = k²
2x² + 2y² + 2z² − 4x − 14y + 4z + 109 = k².