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CLASS 11 · MATHEMATICS · CHAPTER 11

Introduction to Three Dimensional Geometry

Locate points in space, calculate distances and use coordinate relationships. Start with the short working and open the explanation for each method.

29 worked answersAll 2 exercise setsAll 4 end-of-chapter questions

29 worked answers · short steps first, explanations when you need them

Exercise 11.1

Textbook pages 211

Question 1

What are the y- and z-coordinates of a point on the x-axis?

Steps only

P = (x, 0, 0)

Answer

y = 0 and z = 0.

Question 2

What is the y-coordinate of a point in the XZ-plane?

Steps only

P = (x, 0, z)

Answer

y = 0.

Question 3 · point 1

Which octant contains (1, 2, 3)?

Steps only

Signs of (x, y, z): (+, +, +)

Answer

Octant I.

Question 3 · point 2

Which octant contains (4, -2, 3)?

Steps only

Signs of (x, y, z): (+, −, +)

Answer

Octant IV.

Question 3 · point 3

Which octant contains (4, -2, -5)?

Steps only

Signs of (x, y, z): (+, −, −)

Answer

Octant VIII.

Question 3 · point 4

Which octant contains (4, 2, -5)?

Steps only

Signs of (x, y, z): (+, +, −)

Answer

Octant V.

Question 3 · point 5

Which octant contains (-4, 2, -5)?

Steps only

Signs of (x, y, z): (−, +, −)

Answer

Octant VI.

Question 3 · point 6

Which octant contains (-4, 2, 5)?

Steps only

Signs of (x, y, z): (−, +, +)

Answer

Octant II.

Question 3 · point 7

Which octant contains (-3, -1, 6)?

Steps only

Signs of (x, y, z): (−, −, +)

Answer

Octant III.

Question 3 · point 8

Which octant contains (-2, -4, -7)?

Steps only

Signs of (x, y, z): (−, −, −)

Answer

Octant VII.

Question 4(i)

Name the plane determined by the x- and y-axes.

Steps only

x-axis and y-axis ⇒ XY-plane

Answer

XY-plane.

Question 4(ii)

Give the general coordinates of a point in the XY-plane.

Steps only

P = (x, y, 0)

Answer

(x, y, 0).

Question 4(iii)

Into how many octants do the coordinate planes divide space?

Steps only

2 × 2 × 2 = 8

Answer

8 octants.

Exercise 11.2

Textbook pages 213

Question 1(i)

Find the distance from (2, 3, 5) to (4, 3, 1).

Steps only

d² = (x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²

= (2)² + (0)² + (-4)²

= 20

d = 2√5

Answer

2√5 units.

Question 1(ii)

Find the distance from (-3, 7, 2) to (2, 4, -1).

Steps only

d² = (x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²

= (5)² + (-3)² + (-3)²

= 43

d = √43

Answer

√43 units.

Question 1(iii)

Find the distance from (-1, 3, -4) to (1, -3, 4).

Steps only

d² = (x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²

= (2)² + (-6)² + (8)²

= 104

d = 2√26

Answer

2√26 units.

Question 1(iv)

Find the distance from (2, -1, 3) to (-2, 1, 3).

Steps only

d² = (x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²

= (-4)² + (2)² + (0)²

= 20

d = 2√5

Answer

2√5 units.

Question 2

Show that P(−2,3,5), Q(1,2,3) and R(7,0,−1) lie on one line.

Steps only

PQ = √14

QR = 2√14

PR = 3√14

PQ + QR = PR

Answer

The points are collinear, with Q between P and R.

Question 3(i)

Verify that A(0,7,−10), B(1,6,−6), C(4,9,−6) form an isosceles triangle.

Steps only

AB² = 1 + 1 + 16 = 18

BC² = 9 + 9 + 0 = 18

AC² = 16 + 4 + 16 = 36

Answer

AB = BC = 3√2; the triangle is isosceles.

Question 3(ii)

Verify that A(0,7,10), B(−1,6,6), C(−4,9,6) form a right triangle.

Steps only

AB² = 18; BC² = 18; AC² = 36

AB² + BC² = AC²

Answer

The angle at B is 90°.

Question 3(iii)

Verify that A(−1,2,1), B(1,−2,5), C(4,−7,8), D(2,−3,4) form a parallelogram.

Steps only

Midpoint of AC = (3/2, −5/2, 9/2)

Midpoint of BD = (3/2, −5/2, 9/2)

Answer

ABCD is a parallelogram.

Question 4

Find the equation for points equidistant from (1,2,3) and (3,2,−1).

Steps only

(x − 1)² + (y − 2)² + (z − 3)² = (x − 3)² + (y − 2)² + (z + 1)²

4x − 8z = 0

x − 2z = 0

Answer

x − 2z = 0.

Question 5

Find the locus of P whose distances from (4,0,0) and (−4,0,0) add to 10.

Steps only

PA + PB = 10

PB² − PA² = 16x

PB − PA = 8x/5

PA = 5 − 4x/5

(x − 4)² + y² + z² = (5 − 4x/5)²

x²/25 + (y² + z²)/9 = 1

Answer

x²/25 + y²/9 + z²/9 = 1.

Miscellaneous Exercise

Textbook pages 215

Question 1

For consecutive vertices A(3,−1,2), B(1,2,−4), C(−1,1,2), find D.

Steps only

A + C = B + D

D = A + C − B

= (1, −2, 8)

Answer

D = (1, −2, 8).

Question 2 · median from A

Find the median from A in the triangle A(0,0,6), B(0,4,0), C(6,0,0).

Steps only

Opposite-side midpoint = (3, 2, 0)

Median² = 49

Median = 7

Answer

7 units.

Question 2 · median from B

Find the median from B in the triangle A(0,0,6), B(0,4,0), C(6,0,0).

Steps only

Opposite-side midpoint = (3, 0, 3)

Median² = 34

Median = √34

Answer

√34 units.

Question 2 · median from C

Find the median from C in the triangle A(0,0,6), B(0,4,0), C(6,0,0).

Steps only

Opposite-side midpoint = (0, 2, 3)

Median² = 49

Median = 7

Answer

7 units.

Question 3

The centroid of P(2a,2,6), Q(−4,3b,−10), R(8,14,2c) is (0,0,0). Find a, b and c.

Steps only

2a − 4 + 8 = 0 ⇒ a = −2

2 + 3b + 14 = 0 ⇒ b = −16/3

6 − 10 + 2c = 0 ⇒ c = 2

Answer

a = −2; b = −16/3; c = 2.

Question 4

For A(3,4,5) and B(−1,3,−7), find the locus satisfying PA² + PB² = k².

Steps only

(x − 3)² + (y − 4)² + (z − 5)² + (x + 1)² + (y − 3)² + (z + 7)² = k²

2x² + 2y² + 2z² − 4x − 14y + 4z + 109 = k²

Answer

2x² + 2y² + 2z² − 4x − 14y + 4z + 109 = k².

Questions follow NCERT’s Mathematics, Chapter 11 ↗, checked on 2026-10-05. Use our original question summaries and worked answers alongside the questions in your textbook.

Diagrams are drawn from mathematical rules. Learnivelle is not affiliated with NCERT.

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